// MCU BASIC: https://www.basic4mcu.com
// DateTime : 2019-04-15 오후 4:19:19
// by Ok-Hyun Park
//
릴레이 모듈은 1초 딜레이 영향을 안받게 하고싶고
lcd는 1초 딜레이 영향을 무조건 받아야합니다.
그래서 따로 쓰려고 void loop를 두개잡았는데 그러면 안되는거같더라구요.
두개를 합치는법을 알려주세요
고쳐야할 부분 색으로 칠해놨어요 ㅜ
//
#include <LiquidCrystal_I2C.h>
LiquidCrystal_I2C lcd(0x27,16,2);
//
#include <DHT.h>
#define DHTPIN A1
#define DHTTYPE DHT11
DHT dht(DHTPIN,DHTTYPE);
//
int Sensor_pin=A1; // 온습도센서 핀을 A1으로 설정
int LED_R=3,LED_G=4;
int Relaypin1=1; // IN1
//
unsigned long t;
//
void setup(){
  pinMode(LED_R,OUTPUT); pinMode(LED_G,OUTPUT); pinMode(Relaypin1,OUTPUT);
  lcd.init(); lcd.backlight();
  Serial.begin(9600);
  t=millis();
}
//
void loop(){
  if(millis()-t>=1000){ t=millis();
    int h=dht.readHumidity();
    int t=dht.readTemperature();
    Serial.println(h); // 센서값을 시리얼모니터로 전송
    //
    if(h<45)digitalWrite(Relaypin1,LOW);  // 공기에 수분이 부족하면 // 릴레이 ON
    else    digitalWrite(Relaypin1,HIGH); // 릴레이 OFF
    //
    if(h<45){ // 공기에 수분이 부족하면
      lcd.clear();
      digitalWrite(LED_R,HIGH); digitalWrite(LED_G,LOW); // 빨간색 LED ON
      lcd.setCursor(0,0); lcd.print("device on"); // 가습기 작동중 문구 출력
    }
    else{ // 공기에 수분이 충분하면
      lcd.clear();
      digitalWrite(LED_G,HIGH); digitalWrite(LED_R,LOW); // 파란색 LED ON
      lcd.setCursor(0,0); lcd.print("device off"); // 가습기 off 문구 출력
    }
    lcd.setCursor(0,1); lcd.print("humidity: ");
    lcd.setCursor(9,1); lcd.print(h); lcd.print("  ");
  }
}